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To be more clear, let the number be n and the number of digits be x. We represent the number as nxnx-1nx We make a copy of that input and store it in copyOfInput.

It is required that we make a copy because the number to be checked will be changed during the execution of the program and towards the end, we need the original input number to declare whether it is an Armstrong number or not.

We first find the number of digits in the input number. To do so, we construct a String by concatenating the input number with a null string. We can also use the valueOf int method of the String class. The length of the resultant string obtaining using the length method will give us the number of digits in the input number.

We also declare a variable sum and initialise it to zero. This variable will hold the sum of the digits raised to the appropriate powers.

Next, in a while loop, we extract the digits of the input from right to left, raise them to the appropriate power and add to the existing value of sum. To extract the last digit of the number, we find the remainder obtained don dividing that number by 10 using the modulo operator.

The remainder is raised to the power numberOfDigits using the Math. This function returns a double value which we explicitly cast to an int so that we can add it to the existing sum. Now, the last digit of copyOfInpuit will be truncated by diving it with The while loop executes as long as copyOfInput is not zero.

When it is zero, all the digits would have been processed. Finally, we check if sum equals the input number. If it is so, the number is an Armstrong number.

Given below is the complete code for this program.Write a python program to check a number is Armstrong number?

Unless someone is willing to write an entire program for you (which I would, but I don't have the patience to learn an entire new.

Description: A perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself. /*Program to find whether given no.

is Armstrong or not. Example: Input - Output - 1^3 + 5^3 + 3^3 = , so it is Armstrong no. Hope we are able to explain you jJava program to check armstrong number, if you have any questions or suggestions please write to us using contact us form.(Second Menu from top left).

Please share us on social media if you like the tutorial. In this program, you'll learn to check whether a given number is armstrong number or not. You'll learn to do this by using a for loop and a while loop in Java. A positive integer is called an Armstrong number of .

Java program to check number is Armstrong number Armstrong (or Plus Perfect, or narcissistic) numbers is: n-digit numbers equal to sum of nth powers of their digits. OR Armstrong number is a number that is the sum of its own digits each raised to the power of the number of digits gives same number.

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